Andrea T.

asked • 10/31/13

subtitution and Elimination #3b

1)  y=-5x+2
     y=3x-14
 
2)  x+y=0
     5x+y=4

2 Answers By Expert Tutors

By:

Randy B. answered • 10/31/13

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4.8 (14)

Algebra, Prealgebra, Precalculus, Geometry, Mathematics, Reading

Jason S. answered • 10/31/13

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Andrea T.

Hi Jason.  thanks for your answers, but I don't understand #2 at all.  Why multiply by -1,and what do you multiply?   then I don't know how you even got the equations.   Please explain.
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10/31/13

Jason S.

You multiply the top equation by -1 so that the y's will sum to 0 (cancel out) when you add the two equations together.
 
x + y = 0
5x + y = 4
 
(-1)(x) + (-1)(y) = (-1)(0)
 
    -x - y     =    0
+ (5x + y)  = + 4
---------------------
 
5x-1x = 4x
y-y = 0
4+0  = 4
 
So
4x + 0  = 4
4x = 4
 
Divide both sides by 4.
 
4x/4 = 4/4
 
x = 1
 
Now plug 1 in for x:
x + y = 0
 
1 + y = 0
 
Subtract 1 from both sides:
 
1 + y -1 = 0-1
y = -1
 
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10/31/13

Andrea T.

Thanks again!  Jason, having a real hard time using the method I now know with this last one, can you help? I've been at it for about an hour now. 
-1/2x-1/4y=3
1/3x+1/6y=2
 
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10/31/13

Jason S.

Multiply the top equation by 4 and the bottom by 6.
 
-2x - y = 12
2x + y = 12
 
Add them together and you get:
 
0 = 24.  This is always false.
 
Therefore, no solution is possible.
 
Note also that if you change them to y = mx+b format:
y = -2x - 12
y = -2x + 12
 
Since the slopes are the same, they are parallel and never intersect.  Thus, the "No solution" answer is correct.
 
Have a great day.
 
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10/31/13

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