three consecutive integers whos sum is -18

Question

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Answer 1

Hi Elliot;

First integer...x

Second integer...x+1

Third integer...x+1+1

(x)+(x+1)+(x+1+1)=-18

3x+3=-18

Let's subtract 3 from both sides as we proceed to isolate x...

3x+3-3=-18-3

3x=-21

Let's divide both sides by 3...

(3x)/3=-21/3

x=-7

 

-7, -6, -5

 

 

Answer 2

If you make the middle integer =n,  the  one before =n-1 and the one after =n+1

The sum is 3n=-18, n=-6, the middle one and the other two are -7, and -5.