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Question

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A candy company claims that 11% of its plain candies are orange, and a sample of 200 such candies is randomly selected.

a. Find the mean and standard deviation for the number of orange candies in such groups of 200.

μ= ?

σ = ? (Round to one decimal place as needed.)

b. A random sample of 200 candies contains 37 orange candies. Is this result unusual? Does it seem that the claimed rate of 11% is wrong?

 

B. Yes comma because 37 is greater than the maximum usual value.

a. Yes, because 37 is greater than the maximum usual value. Thus, the claimed rate of 11% is probably wrong.

b. No comma because 37 is within the range of usual values.No, because 37 is within the range of usual values. Thus, the claimed rate of 11% is not necessarily wrong.

C. Yes, because 37 is within the range of usual values. Thus, the claimed rate of 11% is probably wrong.

D Yes comma because 37 is below the minimum usual value.Yes, because 37 is below the minimum usual value. Thus, the claimed rate of 11% is not necessarily wrong.

 

Answer 1

a) the mean is np = (200)(0.11) = 22 and standard deviation is np*(1-p) = (22)(0.89) = 19.6

 

b) the result is unusual because 37 out of 200 would be 0.185, which is higher than the claim rate of 0.11.  37 is higher than the maximum usual value, so the claimed rate is wrong.