Inactive Tutor answered • 12/11/15
Tutor
New to Wyzant
The stopping distance would be 40 m because
-500x = -20(1000)
x = -20000/500
= 40m
the answer is B
Amanda K.
asked • 12/10/15Help! Help!
What will be the stopping distance for a 1,000-kg car moving 20 m/s when you apply a force of -500 N?
A. 0.4 m
B. 40 m
C. 400 m
D. 4 m
A. 0.4 m
B. 40 m
C. 400 m
D. 4 m
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