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Question

What will be the stopping distance for a 1,000-kg car moving 20 m/s when you apply a force of -500 N?

A. 0.4 m
B. 40 m
C. 400 m
D. 4 m

Answer 1

The stopping distance would be 40 m because 

 

-500x = -20(1000)

 

x = -20000/500

 

= 40m

 

the answer is B