
Raphael D. answered 12/11/15
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In an isolated system, Bicyclist 1 and Bicyclist 2, each with a mass of 80 kg, collide. Bicyclist 1 was moving to the right at 8 m/s, while Bicyclist 2 was moving to the left at 2 m/s. What is the magnitude of their combined momentum before the crash?
In an isolated system, Bicyclist 1 and Bicyclist 2, each with a mass of 80 kg, collide. Bicyclist 1 was moving to the right at 8 m/s, while Bicyclist 2 was moving to the left at 2 m/s. What is the magnitude of their combined momentum before the crash?
let V1=+8m/s
V2=-2m/s
m=80kg
(momentums (velocities as well) have opposite signs - as if moving to right or left)
Combined momentum before the crash, or, net momentum of the (isolated) system would be:
P=mV1+mV2=80*(8-2)kg*m/s=+480 kg*m/s (directed to right)
which is choice A