
Andrew M. answered 12/09/15
Tutor
New to Wyzant
Mathematics - Algebra a Specialty / F.I.T. Grad - B.S. w/Honors
The common point is where the two lines cross. We need the
point where both equations are valid.
px+qy=r
2px-qy=2r
Adding the equations we have
3px = 3r
divide by 3
px = r
x= r/p
WE can substitute that back into one of the
original equations:
(1) px+qy=r
p(r/p) + qy = r
r + qy = r
qy = 0
y = 0/q
y = 0
The common point occurs at (r/p, 0)