The water trough that is like a half cylinder.!!!!

You are being asked to find the surface area of an open cylinder. To do this, you find the area of the different sections and add them together. You need to find the area around the side plus the area of the circle on bottom. For the water trough, there would not be a circle of metal on the top.

You know that the area of a circle is found using the formula pi times the square of the radius, πr^{2}. Since the diameter is 2, the radius is one, and the area of the bottom of the trough is
**π**. (That's supposed to be pi)

The sides of a cylinder may seem tricky at first, but think about taking the label off of a can. It's actually a rectangle. The formula for the area of a rectangle is length times width; the width of the can label is the height of the can; the length of the rectangle is the circumference of the can.

The formula for circumference is pi times the diameter of the circle, πd.

Circumference of the water trough is **2π**. So the amount of metal in the sides is 2π times 6, or
**12π**.

Add the bottom and the side together: 12π + π = 13π so the amount of metal needed is
**13π **square units**.**

## Comments

The formula for the surface area of a cylinder is:

SA = 2pr

^{2}+ 2prhbut the formula assumes there is a solid circle on each end of the cylinder. Since your trough would not have a circle on top, you could modify the formula by subtracting the area of one circle:

SA = (2pr

^{2}+ 2prh) - pr^{2}= pr

^{2}+ 2prhIn the SA formula, it should be pi wherever it shows a p.

Shouldn't it be half the total surface area of a cylinder? I've always pictured a trough as a semi-cylinder, and it's stated in the original question that it's like half a cylinder.

The problem states that the trough has a height of 6. You could use 1/2 the SA of a cylinder with a height of 12. You're right, that's another way to approach this problem.