Arthur D. answered 11/27/15
Tutor
4.9
(364)
Forty Year Educator: Classroom, Summer School, Substitute, Tutor
(7cscx+7)(7cscx-7)
FOIL
49csc2x-49
49(csc2x-1)
csc2x=1+cot2x
substitute
49(1+cot2x-1)
49cot2x seems to be the simplest form although cot=1/tan and cot=cos/sin
or, csc2x-1=cot2x and then substitute to get 49cot2x