2sin(pi/3x) =sqrt2

Question

Find all solutions on the interval 0< (or equal to) theta < 2pi

 

Help! Show steps please.

thanks

Answer 1

2sin(pi/3x)=√2

sin(pi/3x)=√2/2

sin(60/x)=√2/2

sin(45º)=√2/2

sin(135º)=√2/2

60/x=45

x=60/45

x=4/3

60/x=135

x=60/135

x=4/9