solve the equations below in radians

Question

solve the equations below in radians and find all possible values for t in the interval 0≤t≤2pi

 

cos(t)=0 when t=

sin (t)= 1/2 when t =

cos (t)= √3/2 when t= 

tan (t)= -1 when t= 

 

*each question could have more than one answer! 

Answer 1

cos (t) = 0 when t = [(pi)/2] radians

sin(t) = 1/2 when t = [(pi)/6] radians

cos(t) = √3/2 when t = [(pi)/6] radians

tan(t) = -1 = [-(pi)/4] radians or [3*(pi)/4] radians