Mark M. answered 11/15/15
Tutor
4.9
(952)
Retired math prof. Very extensive Precalculus tutoring experience.
Let A(t) = amount remaining in t days
A(t) = A0ekt, where A0 is the initial amount and k is a constant
= 300ekt
Since the half life is 140 days, A(140) = 150 = 300e140k
0.5 = e140k
ln0.5 = 140k
k = -0.00495
So, A(t) = 300e-0.00495t
b). amount in 1 year = A(365) = 300e-0.00495(365)
= 300e-1.80675
= 49.2 mg
c). Find t so that A(t) = 200:
200 = 300e-0.00495t
0.6666666 = e-0.00495t
ln(0.666666) = -0.00495t
t = 81.9 days