Mark M. answered 11/15/15
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Retired math prof. Very extensive Precalculus tutoring experience.
P(t) = 73.2/(6.1 + 5.9e-0.02t)
a). population in 2200 = P(200) = 73.2/(6.1+5.9e-4)
= 11.8 billion
b). The population reaches 10 billion when
10 = 73.2/(6.1+5.9e-0.02t)
61+59e-0.02t = 73.2
e-0.02t = 0.2067797
-0.02t = ln(0.2067797)
t = 78.8 years after 2000 (in the year 2078)
c). As t gets larger and larger, e-0.02t gets closer and closer to 0.
So, P(t) approaches 73.2/(6.1 + 5.9(0)) = 12 billion