Don L. answered • 11/11/15
Tutor
5
(18)
Fifteen years teaching and tutoring basic math skills and algebra
Hi, solving inequalities is like solving an equation, with one exception. Later on the exception.
For 15/x ≤ 3, multiply both sides by x to clear the fraction giving:
15 ≤ 3x
Divide both sides by 3 to solve for x:
5 ≤ x
On a number line, all values to the left of and including 5 would satisfy the inequality.
----+----0----]----+
<---------- ≤5
For 12/3x > 4, multiply both sides by 3x to clear the fraction giving:
12 > 12x
Divide both sides by 12 to solve for x:
1 > x
On the number line, all values to the left of 1 would satisfy the inequality.
----+----0-)---+----+
<-------- <1
<-------- <1
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Example, is the CASE # 1, and CASE # 2
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11/11/15
Don L.
tutor
Hi, normally I use the cases when I am working with absolute values inequalities where multiple solutions are involved. Here, there is only one solution for each of the inequalities, and no need to use a different case.
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11/11/15
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11/11/15