Raymond B. answered 12/07/25
Math, microeconomics or criminal justice
did you mean a box of 11 has 5 that are defective?
most parts that can be defective are 11, 55 is impossible.
if 5 defectives, then:
a) first 2 chosen are good. 1st chosen is good has probability 6/11, 2nd then has probability 5/10=1/2
6/11 x 1/2 = 3/11 odds
b) at least 1 of 1st 3 are good = 1 minus odds all 3 are defective = 1- (5/11)(4/10)(3/9) = 1- 2/33= 31/33
c) first 3 chosen are good multiply a) by 4/9 to get 3/11 x 4/9 = 4/33 odds