Mark M. answered 10/27/15
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Retired math prof. Very extensive Precalculus tutoring experience.
Since P(x) has real coefficients, complex roots occur in conjugate pairs.
So, since 4i is a root, so is -4i, and since 4-i is a root, so is 4+i.
Also, since P(x) has degree 4, it can't have more than 4 roots.
P(x) = 3[x-4i][x-(-4i)][x-(4-i)][x-(4+i)]
= 3(x2+16)[(x-4)+i][(x-4)-i]
= 3(x2+16)[(x-4)2-i2]
= 3(x2+16)(x2-8x+17) = 3(x4-8x3+17x2+16x2-128x+272)
= 3(x4-8x3+33x2-128x+272)
= 3x4-24x3+99x2-384x+816