1/8sin29.5cos29.5

Question

I know that i should multiply something to it for it to become 2sinAcosA for me to be able to solve it. Unfortunately, if i multiply2/2 to it will just become 2/16 that will just bounce back to 1/8 help pls!

Answer 1

Hi Badi,

 

You were on the right track trying to express a relationship in terms of sin2A (2sinAcosA):

    (2/2)(1/8)[sin(29.5)][cos(29.5)] = [2sin(29.5)cos(29.5)]/16

    [2sin(29.5)cos(29.5)]/16 = sin[2(29.5)]/16

    sin[2(29.5)]/16 = [sin(59)]/16

    [sin(59)]/16 = 0.0538 

 

Thanks for submitting this problem and glad to help.

 

God bless, Jordan (Isaiah 53)