Bruce Y. answered 10/19/15
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We set up the problem as 623/c < 7/1
Now we can cross-multiply to get 623x1 < 7xc or 623 = 7c
Divide both sides by 7, and we have 89 < c or c > 89
So c can be any number of computers that is 90 or more, which is answer a.
Izzy B.
Thank you!11/04/21