Brett S. answered 10/19/15
Tutor
New to Wyzant
General Science, Chemistry and Biology Tutor
Hello Mia!
You will want to start with this formula:
A = Pert
Where,
A = The final amount of bacteria
P = The initial amount of bacteria
e = The a mathematical constant that is the base of the natural logarithm (found on your calculator)
r = growth or decay rate
t = time
So, for part (a) you will define A(t) by first finding the growth rate (r) given that you initially have 100 bacterial (P) and after 1 hour (t) you have a final population of 420 bacteria (A) as:
A = Pert
420 = 100er(1)
4.2 = er(1)
ln(4.2) = r
So, you can define A(t) as,
A(t) = 100e(ln(4.2))(t)
Part (b) asks for the growth rate so you will use the rate (r) used for above and the amount of bacteria after 3 hours (A(t)):
A(3) = 100e(ln(4.2)(3)
A(3) = (100)(4.23)
dP/dt = r(A(t)) = ln(4.2)(A(3))
And (c) gives you a final population of 10,0000 bacteria (A) and you can now plug that into your expression from part (a) to find the time it will take to reach that population:
10000 = 100e(ln(4.2))(t)
100 = e(ln(4.2))(t)
ln(100) = (t)ln(4.2)
t = ln(100)/ln(4.2)
I will let you plug in the numbers and practice it yourself, let me know if you still have questions and I hope this has helped!
Brett S.
Hi Mia,
The two equations are actually the same, I just left the natural log 'ln' and base 'e' in the equation so you could see the way that the original equation was rearranged. If you follow logarithmic rules, the natural log 'ln' and the base 'e' will actually cancel each other out!
You can test this by applying a number for the variable t in both of the equations and you will get the same answer, for example:
A(t) = 100e(ln(4.2))(3) where t = 3
If you put this in your calculator your will get 7408.8
f(t) = 100(4.2)(3) where t = 3
If you put this in your calculator you will also get 7408.8
So, these two equations are the same but your textbook is using a more reduced form after taking the logarithmic expressions out of the equation.
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10/29/15
Mia L.
10/29/15