Pia R.

asked • 10/19/15

Tan(theta+30)

tana+tanb/1-tanatanb
 
im confused becase sqrt of 3 over 3 is the value of tan 30 so its hard to solve the arithmetic and the algebra. help please!

Bads L.

Thanks for answering! how did sq rt of 3/3 became 1/ sq rt of 3
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10/19/15

Sirisha R.

√3 * √3 = 3,  so  √3/3 = √3/(√3 * √3) = 1/√3 
 
Alternatively √3/3 = 1.732/3 = 1/1.732 = 1/√3
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10/19/15

Bads L.

Thank you sirisha r!
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10/19/15

1 Expert Answer

By:

Sirisha R. answered • 10/19/15

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tan(θ+30)
 
value of tan30 is √3/3
which is 1/√3                            [Since (√3)2=3]
 
(tanθ+tan 30)/(1-tanθtan 30)
=(tanθ+1/√3)/(1-tanθ.1/√3)
=[(√3.tanθ+1)/√3]/[(√3-tanθ)/3]
=(√3.tanθ+1)/(√3-tanθ)
Please let me know if you have questions
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