
Angelica D. answered 10/14/15
Tutor
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f(x)= {[(x3)+1]}1/2
y = {[(x3)+1]}1/2
x = {[(y3)+1]}1/2
x2= {{[(y3)+1]}1/2}2
x2=y3+1
x2-1=y3
y=(x2-1)1/3
f-1(x)=(x2-1)1/3