Mark N.

asked • 10/11/15

Trigonometry Question - HELP

A river running due east has straight parallel banks. A vertical post stands with its base, P, on the north side of the river. On the south bank are two surveyors, A who is to the east and B who is to the west of the post. A & B are at a distance 2/7a apart and the angle APB = 150 degrees. The angles of elevation from A and B of the top Q, of the post are 45 degrees and 30 degrees. Find in terms of a, the width of the river and the height of the post.

1 Expert Answer

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Mark N.

That was really helpful thank you. I'm stuck on the last part, trying to find AP and BP. Using the tangents of the elevation angles, I find AP to be = h (height) and BP = sqrt(3)*h (height). Then I use the sin rule inside the horizontal plane triangle to get width = 7sqrt(3)h^2/4a. I'm not sure what to do next. Thanks.
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10/11/15

Mark N.

here is my working: oi58.tinypic. com/2nuupsp.jpg
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10/11/15

Mark N.

Okay Solved it - oi61.tinypic. com/2hov0ic.jpg
Thank you so much for your guidance and help!
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10/11/15

Kyle M.

tutor
I'm not able to see your working, but I've since taken a closer look at the solution. I believe the key to this is the proportion of AB that is allocated to AP & BP. On the side view, the post is a vertical line that makes a right angle to the ground. This creates a 45 degree angle (AQP) & a 60 degree angle (BQP) at the apex Q. 45 & 60 share a common factor, 15, which we can use to divide AB into equal parts. 45 is 3x15 & 60 is 4x15, so we have 7 equal parts. AP is therefore 3/7 of the measure of AB, while BP is 4/7 of the measure of AB. The measure of AP is, of course, also the height of the post.
 
I found that the river is about 0.0375a wide.
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10/12/15

Mark N.

If you delete the space between the '.' and com you should be able to see the solution I wrote in the link. The answer in the book says Sqrt(3)(a)/49, which is what I got too.
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10/12/15

Kyle M.

tutor
I probably used the wrong measure of AB. I'm glad you worked it out. Good job!
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10/12/15

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