J.R. S. answered 10/10/15
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A reducing agent is one that loses electrons and itself becomes oxidized.
2Cr(OH)3+3OCl−+4OH−→2CrO4−2+3Cl−+5H2O
Cr on the left has ox.no. of +3 and on the right it is +6, so it has been oxidized and is the reducing agent.
Cr^3+ ==>Cr^6+ + 3e-