-1/2(x-2)^4/3=1-3^2

Question

How would I go about this question in solving for x?

Also, what kind of problem would this be considered to practice other similar problems?

 

-1/2(x-2)^4/3=1-3^2

Answer 1

-1/2(x-2)^4/3=1-3²

=>-1/2(x-2)^4/3=1-9 ... By adjusting operators

=>-1/2(x-2)^4/3=-8 ... By adjusting operators

=>1/2(x-2)^4/3=8 ..... By multiplying both sides by (-1)

=>(x-2)^4/3=16..... By multiplying both sides by 2

=> (x-2)⁴= 16³ ..... By cubing both sides

=> (x-2)⁴= (2⁴)³ ... By adjusting operators

=> (x-2)⁴= (2³)⁴ ... By adjusting operators

=> x-2= 2³ ... By deriving 4th root of both sides

=> x-2=8... By adjusting operators

=> x=8+2... By adding 2 to both sides

=>x=10

 

Practice suggestion: Indices