Since the population standard deviation is known, you would use the z-score to find the P-value for this hypothesis.
We have
z = (M-µ)/(σ/√n) =(65-60)/(15/5) = 1.67.
Use a table or the TI-83 or Excel to find the P-value,
P = 0.096
Since P > a=0.05, the result is NOT significant at the 5% level, so you do NOT reject the null hypothesis µ=60.
It is significant at the 10% level though.