This problem is solved by using the formula
C1V1 + C2V2 = C3V3, where C = Concentration and V = Volume
In this case, alloy AG1 will be used to dilute alloy AG3 to produce alloy AG3
Let x = Volume of AG2, then
x$17 + (10oz - x)$13 = 10oz$15
$17x +$130oz - $13x = $150oz
Combining terms, we get $4x = $20oz
Solving, x = 5oz
Thus, mixing 5oz of AG1 at $17 with 5oz at $13 of AG2 will produce 10oz of AG3 at $15.
Proof, 5(17) + 5(13) = 10(15); $85 + $65 = $150