Roman C. answered 09/02/15
Tutor
5.0
(851)
Masters of Education Graduate with Mathematics Expertise
System:
(1): x+y = -1
(2): x+2y = 0
Solution:
(3)=(2)-(1): (x+2y) - (x+y) = 0 - (-1)
x + 2y - x - y = 1
y = 1
Now substitute into (1).
x + 1 = -1
x = -2
So the solution is x = -2, y = 1.
(1): x+y = -1
(2): x+2y = 0
Solution:
(3)=(2)-(1): (x+2y) - (x+y) = 0 - (-1)
x + 2y - x - y = 1
y = 1
Now substitute into (1).
x + 1 = -1
x = -2
So the solution is x = -2, y = 1.