Shradha S. answered 09/01/15
Tutor
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Experienced Maths Teacher with Master's Degree in Mathematics
smaller pulley has radii r1 = 2.7 inches
larger pulley has radii r2 = 4.5 inches
frequency f = 20 rpm
a)angular speed ω2 = 2*pi*f = 2*pi*20=125.66 rad/min.
b)linear speed v = ω2r2 (as belt revolves over larger pulley)
= 125.66 * 4.5
= 551.48 inches/min
c)angular speed of smaller pulley ω1=v/r1 = 551.48/2.7 =204.25 rad/min.