Roman C. answered 08/27/15
Tutor
5.0
(853)
Masters of Education Graduate with Mathematics Expertise
Let n be the number of nights spent.
Since the first two nights are each $75, if n≤2, the $75n
Since each additional night after that, is $50, if n>2, such a client pays $150 for the first 2 nights and $50 for each of the other n-2 nights for a total of $[150+50(n-2)] = $(50n+50)
So the function for the cost is
C(n) = 75n for n ≤ 2
C(n) = 50n+50 for n > 2
I'm not sure why you added trigonometry as the topic for this question.
Chimnecherem A.
This is marvelous.03/09/21