
Arturo O. answered 06/02/16
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Dale moves at speed v for a time t to reach the intercept point d = vt
t = d/v
Ruby walking: Ruby moves at speed 2v to reach d, but she started 5 minutes late, so she reaches d at time:
t1 = 5 + d/(2v) minutes
Ruby on bicycle: Ruby moves at speed 3v to reach d, but started 5 minutes late plus an extra 2 minutes late, so she reaches d at time:
t2 = (5+2) + d/(3v) = 7 + d/(3v)
Now find out how far Dale moves over the times t1 and t2, and pick the option in which he moves the smaller distance.
Ruby walking:
v*t1 = d1
v*[5 + d1/(2v)] = d1
5v + (1/2)*d1 = d1
d1 = 10v
Ruby bicycling:
v*t2 = d2
v*[7 + d2/(3v)] = d2
7v + (1/3)*d2 = d2
d2 = (21/2)*v
Compare d1 and d2, and see that d1 < d2, so Ruby intercepts Dale sooner when running than when bicycling.