Roman C. answered 08/26/15
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When P(t) < 500, we must have dP(t)/dt > 0 and approaching 0 as P(t) approaches 500.
This happens to choice "a", dP(t)/dt= k(500-P(t)) only. You can see it as 500-P(t) → 0+ as P(t) → 500 and multiplication of that difference by a constant k won't change this limit.
Be careful, choice "d" is a trap answer as it only is valid for k=1 but we want a choice that is valid for all k>0.