sine and cosine

Question

sec x=sin2x/sinx - cos2x/cosx

Robert F. · Accepted Answer

sec x=sin2x/sinx - cos2x/cosx
 
sec x=2sinxcosx/sinx-(cos2x-sin2x)secx
 
secx=2cos2xsecx-(cos2x-(1-cos2x))secx
 
secx=2cos2xsecx-(cos2x-(1-cos2x))secx=secx

Mark M. · Answer

sin(2x)/sinx - cos(2x)/cosx = 2sinxcosx/sinx - (2cos2x - 1)/cosx
 
                                                   = 2cosx - 2cos2x/cosx + 1/cosx
 
                                                   = 2cosx - 2cosx + 1/cosx
 
                                                   = 1/cosx
 
                                                   = secx

sine and cosine

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sine and cosine

2 Answers By Expert Tutors

Still looking for help? Get the right answer, fast.

OR

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