
Shradha S. answered 08/16/15
Tutor
4
(1)
Geometry Concepts
1) Y (0,5) and M (3,3)
let the coordinates of point Z be (x',y')
Mid point of two points with coordinates (x1,y1) and (x2,y2) will be =( (x1+x2)/2 , (y1+y2)/2 )
So M (3,3) = ( ( 0+x')/2 , (5+y')/2 )
and equating x-coordinates and y coordinates on both side separately we get,
3= x'/2 and 3 = (5+y')/2
3*2 = x' and 3*2 = 5+y'
6 = x' and 6 = 5+y'
6-5= y'
1 = y'
So coordinates of M = (x',y') = (6,1)
In similar way solve for the next part..