Arthur D. answered 07/30/15
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You're right, Danette.
a^4/a^1=a^(4-1)=a^3
b^(-3)/b^(-2)=b^(-3-[-2])=b^(-3+2)=b^(-1)=1/b
put them together to get a^3/b
another way to look at this is...
b^(-3)/b^(-2)=(1/b3)/(1/b2)=(1/b3)*(b2/1)=(b2/b3)=1/b
basically, b^(-3) in the numerator means b^3 goes into the denominator
also, b^(-2) in the denominator means b^2 goes into the numerator
b^2/b^3=1/b again if you want to remember it this way