
Dr. Neal G. answered 07/29/15
Tutor
5
(3)
Princeton Ph.D. retired engineering professor
The problem solution goes as follows
G = number of general admission tickets
S = number of student tickets
G = S is given
Cg is the cost of the general admission ticket
Cs is the cost of the student ticket
Cg = Cs + 6
The total amount collected for general admission is
3000 = G*Cg = G*(Cs + 6)
The total amount for student tickets is
1800 = S*Cs = G*Cs because G = S
So now you have two equations and two unknowns. These are
3000 = G*(Cs+6)
1800 = G*Cs
Subtract the second equation from the first
1200 = 6*G means G = 200 and S = 200
that means 1800 = 200*Cs or Cs = 9. This means Cg = Cs + 6 = 15. So the answer is 'd'