Find the exact values of sin2? cos2? and tan2?

Question

Find the exact values of sin2θ cos2θ and tan2θ

for sinθ= -12/13; 270<θ<360

 i got 

sin2θ=120/169

cos2θ=-119/169

and tan2θ=120/119

Answer 1

Sin θ = -12/13

Cos θ = 5/13

Tan θ = -12/5

 

Sin 2θ = 2*sin θ * cos θ = 2(-12/13)(5/13) = -120/169

Cos 2θ = 2*cos² θ - 1 = 2(5/13)² - 1 = -119/169

Tan 2θ = (sin 2θ)/(cos 2θ) = 120/119