given logb4 = 0.7124 and logb12 = 1.2770 find the following

Question

A) logb3

 

B) logb8

Answer 1

B).  log_b8 = log_b(2³) = 3log_b2

 

       Find log_b2:    We know log_b4 = 0.7124

 

                               log_b4 = log_b(2²) = 2log_b2

 

                               So, log₂2 = ½log_b4 = ½(0.7124) = 0.3562

 

       Therefore, log_b8 = 3log_b2 = 3(0.3562) = 1.0686

Answer 2

log_b3 = log_b(12/4)

log_b3 = log_b12 - log_b4

log_b3 = 1.2770 - 0.7124

log_b3 = 0.5646

Answer 3

What do you mean by "b4" and "b8" ?