two difficult questions to answer

Question

1) SOLVE:

 

(Y=1/3 SIN(X-Π/6)

AMP=

PERIOD=

PHASE=

 

 

 

2)CSC (-240°)   SOLVE FROM DEGREE TO RADIAN

 

REF ANGLE+

RADIAN=

Answer 1

1. AMP = 1/3

 

   PERIOD = 2∏/1 = 2∏

 

   PHASE SHIFT = ∏/6 (to the right)

 

2. CSC (-240)  If you go 240 clockwise from zero, that's the same as counterclockwise by 360 - 240 = 120. So that's the 2nd quadrant. The ref angle is 180 - 120 = 60^o  .

In radians, -240 = -240/180 * ∏  = -4/3∏. The ref angle = ∏/3

Answer 2

1) (Y=1/3 SIN(X-Π/6)

Asin(p(x)-w) A = amp, 2(pi)/p = period, w/p = phase shift

Amp=1/3

period=2(pi)/1=2(pi)

phase shift=(pi)/6/1=(pi)/6

 

2)CSC (-240°) SOLVE FROM DEGREE TO RADIAN

 

degrees to radians (-240°/360°) * 2(pi) = -1.334(pi)

 

CSC (-1.334(pi))=-13.6837