Shivansh P.
asked 07/03/15Solve for x: x^19 - 2x^18 + 7x^17 - 12x^6 + 6x^15 = 0
Solve for x: x^19 − 2x^18 + 7x^17 − 12x^6 + 6x^15 = 0
Please help and thank you!
Full answer please!
Full answer please!
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1 Expert Answer
Assuming that x6 should be x16, we have:
x15(x4 - 2x3 + 7x2 - 12x + 6)
1 is a root of the second factor. Divide the second factor synthetically by x - 1:
1⌋ 1 -2 7 -12 6
1 -1 6 -6
1 -1 6 -6 0
So, the original polynomial = x15(x-1)(x3-x2+6x-6)
1 is a root of x3-x2+6x-6. Divide synthetically by x-1:
1⌋ 1 -1 6 -6
1 0 6
1 0 6 0
The original polynomial = x15(x-1)2(x2 + 6)
Setting the polynomial equal to zero, we get x = 0, 1, √(6)i, -√(6)i
Shivansh P.
Sorry typo yes you are correct thank you very much!
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07/04/15
Michael J.
Mark, you made an error when factoring the (x2 + 6) term in your solution. Starting from your factor
(x + 6i)(x - 6i) = x2 - 36i2
= x2 - 36(-1)
= x2 + 36
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07/04/15
Mark M.
tutor
Michael: Thank you for spotting the error. I have made the correction.
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07/04/15
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Maria T.
07/03/15