We started with Joel and Sharon had $400 total
Let J = starting money for Joel
Let S = starting money for Sharon
J + S = 400
Joel gave away (3/7)J to S and Sharon gave 3/8(S) to J and they had equal amounts at that time ($200 each)
J - (3/7)J + (3/8)S = S - (3/8)S + (3/7)J
(4/7)J + (3/8)S = (5/8)S + (3/7)J
Putting this all to the left side of the = sign we have:
(4/7)J - (3/7)J + (3/8)S - (5/8)S = 0
(1/7)J - (2/8)S = 0
(1/7)J - (1/4)S = 0
To simplify this by eliminating fractions multiply through by 28
4J - 7S = 0
We now have two equations we can easily work with
J + S = 400 eqn 1
4J - 7S = 0 eqn 2
Solve for one variable in terms of the other in eqn 1... Let's try solving for J
J = 400-S
Substitute that into eqn 2 and solve for S
4(400-S) - 7S = 0
1600 - 4S -7S = 0
-11S = -1600
S = (-1600)/(-11)
S = 145.45
Sharon started with $145.45
Joel started with 400 - 145.45 = $254.55
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Another way to set up the equations is using the fact that they both had $200 after the exchange.
From that we have:
(4/7)J + (3/8)S = 200 eqn 1
(3/7)J + (5/8)S = 200 eqn 2
Let's eliminate one variable by adding the equations. Multiply eqn 1 by -3 and eqn 2 by 4.
(-12/7)J - (9/8)S = -600 ... (eqn 1)(-3)
(12/7)J + (20/8)S = 800 ... (eqn 2)(4)
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11/8 S = 200
S = 200(8/11)
S = $145.45
J = 400 - 145.45 = $254.55
Andrew M.
06/25/15