Mai V.

asked • 06/24/15

Joel and Sharon had $400 altogether. Joel gave away 3/7 of his money to Sharon. Sharon then gave 3/8 of her money to Joel.

After that, they had the same amount of money.
 
Question: How much money did Joel have at first?

2 Answers By Expert Tutors

By:

Andrew M. answered • 06/25/15

Tutor
New to Wyzant

Mathematics - Algebra a Specialty / F.I.T. Grad - B.S. w/Honors

Andrew M.

Another way to set up our equations is:
 
(4/7)J + (3/8)S = 200  eqn 1
(3/7)J + (5/8)S = 200  eqn 2
 
Multiply eqn 1 by -3  and  multiply eqn 2 by 4 to eliminate J
 
(-12/7)J - (9/8)S = -600
(12/7J  + (20/8)S = 800
___________________
 
               (11/8)S = 200   by adding the 2 equations
 
S = 200(8/11) = 1600/11  = $145.45
J = 400 - 145.45 = $254.55
 
Same answer... possibly not as confusing
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06/25/15

Andrew M.

Another way to set up the equations is:
 
(4/7)J + (3/8)S = 200     eqn 1
(3/7)J + (5/8)S = 200     eqn 2
 
Multiply eqn 1 through by -3 and eqn 2 by 4 so we can add them together and eliminate J
 
(-12/7)J - (9/8)S = -600
  (12/7)J + (20/8)S = 800
_____________________
 
11/8 S = 200
 
S = 200(8/11)
 
S = 145.45
 
J = 400 - 145.45 = 254.55
 
Same answer.  I checked by plugging back into the original equations and the answer is correct.
Both Sharon and Joel have $200 in eqn 1 and eqn 2.
 
 
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06/25/15

Mai V.

(1/7)J - (2/8)S = 0
(1/7)J - (1/4)S = 0
 
How you know?
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06/25/15

Karla V. answered • 06/24/15

Tutor
4.9 (50)

Nursing Student

Andrew M.

Sharon did not have $200 after giving away 3/8 of her money...
She had $200 after giving away 3/8 of her money and adding 3/7 of Joel's money.
The same type of error applies to Joel's money.
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06/25/15

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