Tanveer K.

asked • 05/31/15

The boys can be arranged in 12, 15 and 18 equal rows and also into a solid square what is the least number of boys that school have?

(Hint: find the LCM)

David W.

Matt H. is also quite correct.  The set must contain pairs of each element in order to produce a square result.  The set is {2,2,3,3,5,5) and the product is 2*2*3*3*5*5 = 900.
 
This may also explain why you selected "Square Root" in connection with this problem.
Report

05/31/15

2 Answers By Expert Tutors

By:

Matt H. answered • 05/31/15

Tutor
5.0 (335)

PATIENT :-) Elem/Middle MATH and WRITING; HS SAT and COLLEGE ESSAYS!

David W. answered • 05/31/15

Tutor
4.7 (90)

Experienced Prof

Mark M.

The LCM is not the union of the set of prime factors. If it were another 2 and two more 3's would be included.
Report

05/31/15

David W.

Mark M. is quite correct.  This is what I get from editing and re-editing my sentences until they are meaningless.
Report

05/31/15

David W.

Alas, Mark H. is also read the entire problem and is quite correct.
 
The solution set must have two of each factor (so the set can produce a product that is a square).  The correct set is {2,2,3,3,5,5} and the product is 2*2*3*3*5*5 = 900.
Report

05/31/15

David W.

Matt H. is also quite correct.  The set must have two of each element so that the product will be a square.  The set is {2,2,3,3,5,5} and the product is 2*2*3*3*5*5 = 900.    Now I think I know why you selected "Square root" to classify this problem.      (The square root of 900 is 30)
Report

05/31/15

Still looking for help? Get the right answer, fast.

Ask a question for free

Get a free answer to a quick problem.
Most questions answered within 4 hours.

OR

Find an Online Tutor Now

Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.