Question below.

Question

A slow train left new york at 9:17 am and arrived at pelham at 12:02 pm. On the same day, the express train left new york at 9:56am and arrived at pelham at 11:36 am. At what time did the express train pass the slow train if each was travelling at constant speed

Answer 1

t · r_f = (t + 39)r_s, and r_f = 1.65r_s, so

 

t (1.65r_s) = (t + 39)r_s

1.65tr_s = tr_s + 39r_s

0.65tr_s = 39r_s

0.65t = 39

t = 60

 

The fast train passed the slow train at 10:56 am.