
Taylor G. answered 05/28/15
Tutor
0
(0)
College Sophomore--Math Tutor
I think you have to use logs. So you take the log of the function so you get y=log^(x+2) and then you are able to bring down the (x+2) in front of the log so it looks like this: y= (x+2)log(1/4)
Then you can rewrite that as y=(log(1/4))x +2log(1/4)
Next, the 2 can be brought up and raised by the (1/4), squaring it, making it log(1/16)
Then, subtract (log(1/4))x so it looks like: -(log(1/4))x= log(1/16)
Then, divide log(1/16) by -log(1/4) so that x is by itself.
x= (log(1/16))/ (-log(1/4))
and you should get x=-2
But if you plug the original problem in the calculator and graph it you can see the points by looking at the table.