3log8(2x+7)+8=10

With any question in this form, we always first completely isolate the 'log' part of the function, and then solve from there. To get the log_{8}(2x+7) alone, we solve for it just as we would solve for any other variable.

**3log _{8}(2x+7)+8=10**

-8 -8

**3log _{8}(2x+7) = 2**

/3 /3

**log _{8}(2x+7) =2/3 **

Here we need to remove the log term. We know that log_{b}(x) = n is the same thing as saying b^{n }= x. So, we raise 8 to the power of both sides. This gets rid of the log_{8 }term. So:

**2x + 7 = 8 ^{2/3}**

**2x+7 = 4** and from here we can solve like any other equation

-7 -7

**2x = -3**

/2 /2

**x = -3/2**