logarithms

Question

write log₄ 3y

              x+1

 

as a sum or difference of multiples of logarithms.

Answer 1

Use the following log rules:

• log(a/b) = log(a) - log(b)
• log(ab) = log(a) + log(b)

 

log₄(3y/(x+1)) = log₄(3y) - log₄(x+1) = log₄(3) + log₄(y) - log₄(x+1)