Stephanie M. answered 05/15/15
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FOR AN EXACT ANSWER:
Let's get a better idea of the right triangles associated with each angle.
sin(x) = opposite/hypotenuse = -6/10, so x's opposite side is 6 and its hypotenuse is 10. Solve for the other leg of the triangle using the Pythagorean Theorem:
c2 = a2 + b2
102 = 62 + b2
100 = 36 + b2
64 = b2
8 = b
The angle's adjacent side is b = 8. So:
sin(x) = -6/10
cos(x) = -8/10 (cosine is negative in Quadrant III)
tan(x) = 6/8 (tangent is positive in Quadrant III)
tan(y) = opposite/adjacent = 4/5, so y's opposite side is 4 and its adjacent side is 5. Solve for the hypotenuse of the triangle using the Pythagorean Theorem:
c2 = a2 + b2
c2 = 42 + 52
c2 = 16 + 25
c2 = 41
c = √(41)
The triangle's hypotenuse is c = √(41). So:
sin(y) = -4/√(41) (sine is negative in Quadrant III)
cos(y) = -5/√(41) (cosine is negative in Quadrant III)
tan(y) = 4/5
Now, you can use the Trigonometric Subtraction Formula for cosine, plugging in the values above:
cos(x - y) = cos(x)cos(y) + sin(x)sin(y)
cos(x - y) = (-8/10)(-5/√(41)) + (-6/10)(-4/√(41))
cos(x - y) = 40/(10√(41)) + 24/(10√(41))
cos(x - y) = 20/(5√(41)) + 12/(5√(41))
cos(x - y) = 32/(5√(41))
cos(x - y) = (32√(41)) / (5(41))
cox(x - y) = (32√(41))/205
FOR AN APPROXIMATE ANSWER:
Solve for x and for y:
sin(x) = -6/10
x = sin-1(-6/10)
x ≈ -36.87° = 323.13°
That's in Quadrant IV, so we'll need to reflect the angle over the y-axis to find our actual angle (which is in Quadrant III). x = 180° + 36.87° = 216.87°.
tan(y) = 4/5
y = tan-1(4/5)
y ≈ 38.66°
That's in Quadrant I, so we'll need to reflect the angle over the x-axis and then the y-axis to find our actual angle (which is in Quadrant III). -38.66° is the reflection over the x-axis, so y = 180° + 38.66° = 218.66°.
Plug those values into the equation and solve:
cos(x - y) = cos(216.87° - 218.66°)
cos(x - y) = cos(-1.79°)
cos(x - y) = 0.9995