logarithm word problems

Question

if Log(base-B) of 18=a and log(base b) of 6 =c, then log(base b) of b/3=?

Answer 1

log_b b/3 = log_b b - log_b3 = 1-log_b 18/6 = 1 - (log_b18 - log_b6) = 1-a+b

 

Hope this helped.