the formula to solve this question is C1V1 = C2V2
where C = concentration, and V = Volume
V1 times 5.00M = 250ml times 1.5M
V1 = (250ml x 1.5M)/5.0M
V1 = 75ml
Proof: 75ml x 5M = 375; 250ml x 1.5M = 375
Justina G.
asked • 05/03/15nitric acid
how many mL of 5.00 M nitric acid would prepare 250.0 mL of 1.50 M nitric acid?
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