This question is solved by using the formula C1V1 + C2V2 = C3V3, where C = concentration and V = volume
in essence, the 5% vinegar will be used to dilute the 15% vinegar
to make the calculations easier, we will convert the % figures to decimals,
so 5% = 0.05, 8% = 0.08, and 15% = 0.15
let x = the volume of 15% vinegar
then 0.15x + 0.05(390 - x) = 0.08(390)
our equation becomes 0.15x + 19.5ml - 0.05x = 31.2ml
combining, we get 0.1x = 11.7ml
solving, x = 117ml
so, we need 117ml of 15% vinegar to which we will add 273ml of 5% vinegar to make 390ml of 8% vinegar
Proof: 117ml x 0.15 + 273ml x 0.05 = 390 x 0.08
17.55ml of pure vinegar + 13.65ml of pure vinegar = 31.2ml of pure vinegar; 31.2ml = 31.2ml