I need info on triangle

Question

One half of a triangle is labeled BAC.  <B & <A are 45 degrees.  <C=90 degrees.  Base is 28 (AD).  Altitude Line (segment BA) is 21.  The hypotenuse is  divided into 2 (BC=x, & CD =35.  I need (x) which is the line BC. The line AC has no number or letter.   Need (x).   Th for                B                Only angles marked is <A which is divided by line AC into 2   45 degree <s. 

                                                   |  \

                                                   |     \   x

                                                   |        \    C   <c=90 deg

                                     21          |         / \            ( line BD = 35+x)

                                                   |       /    \      35

                                                   |      /      \

                                                   |    /         \

               <=45 deg            A        |  /            \     D  <= 45 deg

                                                   ---------------- 

                                                    |         28    |                    

                                                                  

                                                                      

                                                                          

                                              .-----------------------.  

Answer 1

Something is wrong with the diagram. If what you have is correct, you have a right triangle with each leg being 35 and the hypotenuse being 28 which is impossible. If you try to solve you get...

21^2+28^2=(x+35)^2

441+784=x^2+70x+1225

1225=x^2+70x+1225

0=x^2+70x

0=x(x+70)

x=0 ?????

also look at the numbers 28, 21, and 35; divide each by 7 and get 4, 3, and 5

this is a 3-4-5 right triangle-3^2+4^2=5^2 or 21^2+28^2=35^2