1 Answered Questions for the topic Goniometry
Goniometry
05/01/17
if cos=sin+ 1/(sqrt3) then what is cos^3-sin^3?
I used a^3-b^3=(a-b)(a^2+ab+b^2)
Answer should be a number
I finally got a^3-b^3= 1/(sqrt3)(1+ab)
Can't see what I'm doing wrong.
Please help.
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